Forum :: Lounge :: Tutor for Coding.

Well, I'm not 100% sure on which topic this thread should go under, so I'll put it here. Feel free to move accordingly.

Now, back to the matter at hand. I want to learn how to code, to put it plainly. I'd really appreciate it if anyone could give me some tutoring over MSN or such. Any other means would be acceptable as well, but I would have to download.

Now, I understand that it's kind of a lot to ask, "Please teach me to code," as I'm sure there are multitudes of variables and factors that go into it. But the fact is, I don't know where to start, or where to look. I literally know nothing about it, and would very much like to learn.

Any and all guidence would be greatly appreciated.

Sausage always told me to read a book. Which I still haven't read a whole book over it, but if you want correct programming, then that's what you should do. I started off on the wrong foot, and it messes me up a lot at times. After you read a few books and understand the basic meaning of it, then a tutor would be necessary to teach you how to apply it, or you could just look at a few correct source codes.

---
http://www.addipop.com

Thanks for the tip. I guess i will go online and look for a good book for beginners.   Any other tips or suggestions would be great.

Yes, learn pointers early on.

Plus, good understanding of how memory works would be good. That's how I got started off, and I understand it enough, but there is always room for improvement.

---
http://www.addipop.com

I dont know what that all means, but i guess that's why i'm learning. haha

A pointer is an address to memory.

int lolwut = 5;

int *rawr = &lolwut;

rawr = 5;

lolwut = 10031831;

rawr now equals 10031831

Since rawr is pointed towards lolwut, it changes with it.

That's the basics of pointers, but it gets more difficult once you learn more and more.

I should tell you, every pointer has to be initialized.

int rawr;
rawr = 5;
That is valid because it's not a pointer

int *rawr;
rawr = 5;
That is invalid because rawr is not 'pointing' to anything. It must allocate(create) memory for it. So to fix it:

int *rawr = new int[5];

Allocates 5 int's in rawr.

---
http://www.addipop.com

uuuh...give me a few days to read a book, and then i'll get back to you on that. haha

Addison posted: (17th Sep 2010 05:01 am)

A pointer is an address to memory.

int lolwut = 5;

int *rawr = &lolwut;

rawr = 5;

lolwut = 10031831;

rawr now equals 10031831

Since rawr is pointed towards lolwut, it changes with it.

That's the basics of pointers, but it gets more difficult once you learn more and more.

I should tell you, every pointer has to be initialized.

int rawr;
rawr = 5;
That is valid because it's not a pointer

int *rawr;
rawr = 5;
That is invalid because rawr is not 'pointing' to anything. It must allocate(create) memory for it. So to fix it:

int *rawr = new int[5];

Allocates 5 int's in rawr.

---
If money doesn't grow on trees, then why do banks have branches?

Yes, rawr turns into an array. So rawr[0-4] is now valid since we created 5 ints. But if you do rawr[10] it will fail.

---
http://www.addipop.com